CraigsMaths

Mathematics Teaching for Learning

Finding determinants of a 3×3 matrix

CraigsMaths
Mathematics Teaching for Learning
Determinants, Engineering Maths B
August 8th, 2008 by admin
Permalink: http://www.craigsmaths.com/ea003-engineering-mathematics-b/finding-determinants-of-a-3x3-matrix/

It is fairly simple to memorise the formula for the determinant of a 2×2 matrix:

\mathit{A}=\begin{bmatrix}<br />
a & b \\<br />
c & d<br />
\end{bmatrix}

\left|\mathit{A} \right|=ad-cb

Here we look at a simple approach that aids memorising the formula for a 3×3 matrix called Sarrus’ rule which will give you the determinant of a 3×3 matrix.

Example

We will find the determinant of a 3×3 matrix:

\mathit{A}=\begin{bmatrix}<br />
a & b & c\\<br />
d & e & f\\<br />
g & h & i<br />
\end{bmatrix}

Step 1

Write 2 copies of the matrix side by side:

\left.\begin{matrix}<br />
a & b & c\\<br />
d & e & f\\<br />
g & h & i<br />
\end{matrix}\right|<br />
\begin{matrix}<br />
a & b & c\\<br />
d & e & f\\<br />
g & h & i<br />
\end{matrix}

Step 2

Sum the products of the terms in each diagonal which starts in the top row and ends on the bottom in a left to right direction.

The sum of the products is:

T=aei+bfg+cdh

Step 3

Now sum the products using the diagonals starting from the bottom row.

B=gec+hfa+idb

Step 4

The determinant will be:

\left|\mathit{A} \right|=T-B

\left|\mathit{A} \right|=\left(aei+bfg+cdh\right)-\left(gec+hfa+idb\right)

Hint: If you end up with 3 groups of 3 terms in each of the brackets then all is well.

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2 Responses to “Finding determinants of a 3×3 matrix”

  1. Wilfred Says:

    I must confess that this is a sure easy and smart way of completing finding the determinant of a 3×3 matrix.
    Thanks so much.

  2. Craig Rose Says:

    Glad it helped! I wish bigger matrices were that easy.

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